The vertices of ΔABC are A(1,–2), B(1,1), and C(5,–2). Which could be the side lengths of a triangle that is similar but not congruent to ΔABC?
3, 4, and 5 units
9, 12, and 15 units
6, 4, and 5 units
9, 12, and 5 units
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OpenStudy (anonymous):
@radar
OpenStudy (anonymous):
@magepker728
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
@Loser66
OpenStudy (anonymous):
@toottwin
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OpenStudy (anonymous):
either 9 12 and 15 or 9 12 and 5
OpenStudy (anonymous):
how do you even figure it out?
OpenStudy (anonymous):
i don't know i asked my mom ;)
OpenStudy (anonymous):
I'm sorta busy right now with my homework
OpenStudy (loser66):
hahaha... 9, 12, 15 only
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OpenStudy (anonymous):
how?
OpenStudy (anonymous):
yes ask him
OpenStudy (loser66):
(3,4,5) is a right triangle, right?
OpenStudy (loser66):
and it is exactly your ABC
OpenStudy (loser66):
Hence it cannot be the answer.
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OpenStudy (anonymous):
alright got that part
OpenStudy (loser66):
|dw:1457577013340:dw|
OpenStudy (loser66):
|dw:1457577099514:dw|
OpenStudy (loser66):
|dw:1457577119758:dw|
OpenStudy (loser66):
Hence, your ABC is a right triangle with the sides (3,4,5)
Therefore, the first option is NOT correct since it is congruent to ABC
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OpenStudy (loser66):
Now, 3*(3,4,5) = (9,12,15) is only solution
OpenStudy (loser66):
It makes your triangle 3 times larger than it is and similar to the original one.