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Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneous solution
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\[3\sqrt{x+6}=-12\]
Divide 3 on both sides first.
\[\sqrt{x+6}=-4\] Then I multiply by -1 on each side?
No, we square both sides.
oh that's right this isn't an I equation so itll be x=10 after squaring and subtracting 6
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and now, plug back in x = 10 when you plug back in x = 10, does it work?
no it doesn't
so that means it is an extraneous solution
oh that was pretty easy thought I got the wrong x value thanks again :)
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