Help, will fan and medal, with testimonial!
Factor completely: 3a2 + 5a − 12 A Prime B (3a + 4)(a − 3) C (3a − 4)(a + 3) D (3a − 3)(a + 4)
you can distributive property on each to see if they equal, or you can factor it
I'm trying to factor, but I can never get it quite right
3a2+9a−4a−12 Factor out common terms in the first two terms, then in the last two terms 3a(a+3)−4(a+3) Factor out the common term a+3
where did you get 9a and -4a?
Multiply 3 by -12, which is -36. 2. Ask: Which two numbers add up to 5 and multiply to -36? 3. Answer: 9 and -4 4. Rewrite 5a5a as the sum of 9a9a and −4a−4a:
Okay, I see. I did some math on my side, and (3a-4)(a+3) is the right answer. Thanks for your help! finally understood how to factor that!
yes you are correct and sorry I took long but my computer started typing in japanese so now I have to fix that
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