Question

Algebra II question, please see attachment.

Answer 1

I know the vertex form is \[y=a(x-h)^2 + k\]
The vertex of the parabola is (-1,5)
now it becomes
\[y=a(x-(-1))^2+5\]
I don't know how to solve any further.

Answer 2

Axis of symmetry is

\[-\frac{ b }{ 2a }\]

so we have a polynomial in the form

\[-2x^{2}-4x+3\]

so to find the axis of symmetry first identify the b term and the a term.

\[ax^{2}+bx+c\]

Answer 3

what are the b and a terms?

Answer 4

It's either A, B, or D.