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Hey, I have a question about this problem if anyone can help?
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bring it on
So A rhombuses opposite sides are congruent, so one said has to add up to the 112, so can I figure it out by adding it up?
u mean parrellelogram?
Oh I thought it was a rhombus, but the same rule applies
Anyways, Opposite angles of a parrellelogram are equal
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therefore 112=4b+8
(112-8)/4=.....
26
there we go
How about A, what do I do for A?
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What is the sum of the angles of a quadrilateral?
360
ok so the sum of all the angle presented is 360
Which means 2a+2a+112+112=360
Right? All opposite angles r equal
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...? hello?
Yeah, I'm still here
I'm solving it
k
Okay 34
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yep
nice job!
Call me if u need more help
KK I will!
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