will fan and medal: Which of the following is not a perfect square trinomial? 169 – 26y + y*2 81 + 18y + y^2 64 + 8y + y^2 25 + 10y + y^2
you need to find the square root of the first number and check if the coefficient of the term in x = 2* this square root ( note the root may be positive or negative) If this is the case then we have a perfect square.
OH - and the last term has to be y^2
so my answer would be A??
I notice that its y*2 in the first choice. Could that be a typo?
yes its supposed to be y^2
if its not a typo then one answer is A. But there's another one which id not a perfect square. Try the square root test on B , C and D.
For B for example square root of 81 is 9 and 2*9 = 18 ( in '18x') so that is a perfect square trinomial Get the idea?
Try C what is the square root of 64?
8
8x2=16
ok so have we got a perfect square here?
yes
check 16 against the number thats in front of the term in x
do you mean divide them????? 64/16=4
No what number multiplies x inr multiplies y in 64 + 8y + y^2 Sorry i've been writing x all the time when i should have written y!!.
the number in fron of the y
Its 8 right? (8y)
sorry i've confused you
its fine .......8*16 = 128????
No C is not a perfect square because there is not a 16 infront of the middle term (the term ending in y) - its 8y . If it was a perfect square it would be 16y.
ok so the answer is A???
No the answer is C We are looking for a triniomial which is not a perfect square. A is a perfect square because SQuare root of 169 = -13 and 2*-13 = -26 which is the number in front of the term in y (middle term)
oh......... ok i get it now thank you
good yw A will expand to ( y - 13)(y - 13) - if we expand that we''ll get y^2 - 26y + y^2
* A will factor to
ok got it
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