Question

Easy Medal

Answer 1

Factor.

\[2x^2 - 7x + 6\]


A. \[(2x + 3)(x - 2)\]


B. \[(2x - 3)(x + 2)\]


C. \[(2x - 3)(x - 2)\]


D. \[(2x - 2)(x + 3)\]

Answer 2

One more left!~

Answer 3

@ace-n-it

Answer 4

Given the equation\[f(x)=ax^{2}+bx+c\rightarrow\]

Answer 5

uh.......

Answer 6

You know how to do this?

Answer 7

nope DX

Answer 8

...I just explained to you though... lol\[f(x)=ax^{2}+bx+c\rightarrow\text{ equation given }2x^{2}-7x+6\]So a=2, b=-7, c=6

Answer 9

OH WAIT I DID SOMETHING WRONG

Answer 10

Oh? o-o

Answer 11

Factor.

\[(3x-4)(2x+1)\] <---- (This was the actual equation)


A. \[(2x + 3)(x - 2)\]


B. \[(2x - 3)(x + 2)\]


C. \[(2x - 3)(x - 2)\]


D. \[(2x - 2)(x + 3)\]

Answer 12

o_e wot

Answer 13

That's already factored though, unless they want a reverse distribution (FOIL) to get a polynomial... but the options all have factored results e_e

Answer 14

UM OKAY my teacher just said the correct was (3x−4)(2x+1) she didn't say what was wrong though...

Answer 15

Wait...\[(3x-4)(2x+1)\rightarrow\text{ *brain died* }\]

Answer 16

Yeah. I don't know xD

Answer 17

XD oh well, it's just one more wrong question. :P thanks anyways

Answer 18

Wait what are you confused about?

Answer 19

^ *hands over mic* xD

Answer 20

Why are you confused? Which part do you need help with?

Answer 21

Factor completely.


\[3x^3 - 12x\]


A. \[3x(x - 2)(x - 2)\]


B. \[3x(x - 4)\]


C. \[3x(x + 2)(x - 2)\]


D. \[3(x + 2)(x - 2)\]

Answer 22

New question, move on.

Answer 23

Nuh. You need help on that question. >:|

Answer 24

XD

Answer 25

It is not factorable. I have attempted it with grouping and such but cannot find an answer.

Answer 26

JUST HALP ME WITH THE NEW ONE

Answer 27

Okay.