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OpenStudy (tennis5518):
Cant really factor anymore,,, you can rewrite it though
9a^4 - b^2
9(a^2 + b)(a^2 - b)
OpenStudy (math&ing001):
Come on aloneS I thought you were gonna ask a real question haha
OpenStudy (tennis5518):
Thanks!
alones (alones):
okay i thought thay tooo
OpenStudy (tennis5518):
She probably already know it hehe
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alones (alones):
LOL MATH I WAS SAYING IT IS xP
alones (alones):
No i actually don't /;
alones (alones):
i mean i was checking lel
OpenStudy (tennis5518):
oh oK! <3
Directrix (directrix):
@Tennis5518
This factorization --->9(a^2 + b)(a^2 - b) for the given problem "Factor 9a^4 - b^2"
is incorrect. If you multiply 9(a^2 + b)(a^2 - b), you get 9a^4 - 9b^2 which is not the original problem.
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Directrix (directrix):
Factor with the difference of two squares format:
9a^4 - b^2 = (3a^2 + b) * (3a^2 - b)
@AloneS
alones (alones):
Oh so it's (3a^2 - b)
rather than 9(a^2 + b)(a^2 - b) @Directrix
Directrix (directrix):
All of this is the correct answer: (3a^2 + b) * (3a^2 - b)
Directrix (directrix):
>>Oh so it's (3a^2 - b) Wrong
alones (alones):
Correct Answer: (3a^2 + b) * (3a^2 - b)
Thank you<3
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