Factor 9a^4 - b^2
Cant really factor anymore,,, you can rewrite it though 9a^4 - b^2 9(a^2 + b)(a^2 - b)
Come on aloneS I thought you were gonna ask a real question haha
Thanks!
okay i thought thay tooo
She probably already know it hehe
LOL MATH I WAS SAYING IT IS xP
No i actually don't /;
i mean i was checking lel
oh oK! <3
@Tennis5518 This factorization --->9(a^2 + b)(a^2 - b) for the given problem "Factor 9a^4 - b^2" is incorrect. If you multiply 9(a^2 + b)(a^2 - b), you get 9a^4 - 9b^2 which is not the original problem.
Factor with the difference of two squares format: 9a^4 - b^2 = (3a^2 + b) * (3a^2 - b) @AloneS
Oh so it's (3a^2 - b) rather than 9(a^2 + b)(a^2 - b) @Directrix
All of this is the correct answer: (3a^2 + b) * (3a^2 - b)
>>Oh so it's (3a^2 - b) Wrong
Correct Answer: (3a^2 + b) * (3a^2 - b) Thank you<3
You are welcome.
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