Question

I really need help on 2 questions i have no clue how to do them i will fan and medal.

Answer 1

Ok first the first one, we need to calculate the ion concentration.

Answer 2

To calculate the pH of an aqueous solution you need to know the concentration of the hydronium ion in moles per liter (molarity). The pH is then calculated using the expression: pH = - log [H3O+].

Wiki

Answer 3

Does this question give us the molarity?

Answer 4

I'm asking @edbf123

Answer 5

Moles/Liters = Molairty, right?

Answer 6

Molarity*

Answer 7

Are you still there?

Answer 8

Do you still need help bud?

Answer 9

hey sorry laptop died

Answer 10

im still confused

Answer 11

Well for the first one

Answer 12

The product of the hydrogen ion concentration and hydroxide ion concentration at 25 degrees celcius is \[[H^{+}][OH^{-}] = 1*10^{-14} \]

What you would do is re-arrange your formula and solve for [H]

\[\frac{ k_w}{ [OH^{-}] }= \frac{ 1*10^{-14} }{ 1*10^{-11} } = [H^{+}]\]

the number you get will be the concentration of your hydrogen ions.

Then you take the pH of that which is the -log

\[pH = -\log[H^+]\]

if the ph greater than 7 it's basic
if it's 7 it's neutral
less than 7 acidic.

Answer 13

For your second question they are asking for the acid dissociation constant

\[[HA,ACID] \rightarrow [A^{-}][H^{+}]\]

which is

\[K_{a} = \frac{ [H^{+}][A^{-}] }{ [HA] }\]

Answer 14

thank you