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Am i correct? Simplify i^41. i <--- my answer –1 –i 1
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hmm what's \(\bf i^4=?\) anyway?
Yes, you are correct. It would be i. Since, you have 41 you would find a number that is lower and divides by the number 4. For example, in this case 40 divided by 4 is 10 and so that number would be 1 which is i^4 but your looking for 41so you start at the top again with i and go down but for this case it would only go down one and that would be i.
\[\iota ^{41}=\iota ^{40}\iota =\left( \iota^2 \right)^{20}\iota=\left( -1 \right)^{20}\iota=?\]
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