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Mathematics 7 Online
OpenStudy (ibrafacts):

Does anyone know hero to do this?

Directrix (directrix):

I have constructed this (see attachment) but I did not start off in a rectangle.

OpenStudy (ibrafacts):

wait the leg is 3?

OpenStudy (ibrafacts):

can u start me off please like u do 2 of them please?

Directrix (directrix):

I started with a segment length of 1 and constructed a right angle at one of its endpoints. Then, I joined those sides to from the hypotenuse. Maybe I need to read the question you have again.

OpenStudy (ibrafacts):

all i have rn is the square

Directrix (directrix):

Oh. This is a drawing (easier than construction) You start with a side of length 3 and then draw another 3" side that appears to be vertical to the first segment at the end of that segment.

OpenStudy (ibrafacts):

cm we are using right?

OpenStudy (ibrafacts):

i do a couple can u check please

OpenStudy (ibrafacts):

cuz i have to make like 15 of these and i dont want to mess up

Directrix (directrix):

I did not have that 10 and 15 on mine. Anyway, here is what I did next. Hey, this makes a great diagram once you get the hang of the drawing.

OpenStudy (ibrafacts):

yeah the 15 and 10 is just helping me start it thats what the step 1 said

OpenStudy (ibrafacts):

pleade dont leave @Directrix

Directrix (directrix):

Notice how the hypotenuses are moving from 3√2 to 3√3 to 3√4 (which = 6). Just keep going. Look at my diagram and see if it makes sense. I am using the Pythagorean Theorem to get the hypotenuses. Well, to get the first two, I did. Now, I see the pattern and know what to expect.

OpenStudy (ibrafacts):

yeah i see but how do u know how much to curve it? like the top part?

Directrix (directrix):

At the upper endpoint of the previous hypotenuse, draw a 3 inch long segment perpendicular (makes a right angle). |dw:1457831612729:dw|

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