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Mathematics 8 Online
OpenStudy (christos):

Linear algebra, Can you please tell me what is the reverse of this equivalence relation? - A is nonsingular/invertible - A ~ I - Ax = 0 has only the trivial solution - Ax = b has a unique solution (x = A^-1 * b) So the opposite would be.. - A is singular/non-invertible - ??? - ??? - ???

OpenStudy (christos):

@hartnn @Kainui

OpenStudy (christos):

can someone help me please

OpenStudy (quetzal):

@phi can you help?

OpenStudy (phi):

I know an equivalence relation is reflexive, symmetric and transitive. But what is the definition of "reverse" ?

OpenStudy (phi):

if the "reverse" of A ~ I means A not ~ I then you would interpret that as all objects of type A intersected with all objects of type I is the empty set: \( A \ne I \)

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