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Linear algebra, Can you please tell me what is the reverse of this equivalence relation? - A is nonsingular/invertible - A ~ I - Ax = 0 has only the trivial solution - Ax = b has a unique solution (x = A^-1 * b) So the opposite would be.. - A is singular/non-invertible - ??? - ??? - ???
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@hartnn @Kainui
can someone help me please
@phi can you help?
I know an equivalence relation is reflexive, symmetric and transitive. But what is the definition of "reverse" ?
if the "reverse" of A ~ I means A not ~ I then you would interpret that as all objects of type A intersected with all objects of type I is the empty set: \( A \ne I \)
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