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The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio is one sixth. Find the sum of this infinite series that will be the upper limit of this population. @phi
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78 28 11 32
do your notes have a formula for the sum of a geometric series?
\[\left| r \right|=\frac{ 1 }{ 6 }<1\] \[s=\frac{ a }{ 1-r }\]
a=65
@surjithayer i still dont know how to find r
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@FibonacciChick666
r is the common ratio
SO ... \[s = \frac{ 65 }{ 1 - 1/6 }\]
so the answer is 78 @FibonacciChick666 ?
r is given as 1/6 your answer is correct.
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\[when ~\left| r \right|<1,r^n \rightarrow0 ~as~n \rightarrow \infty \]
thank you.
yw
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