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@Michele_Laino
hint: the new \(x-\) coordinate is: \(x-4\) whereas the new \(y-\) coordinate, is \(y+5\)
for example, for point A, we have: \[\huge A \to \left( {3 - 4, - 1 + 5} \right) = \left( { - 1,4} \right)\]
b---> (7-4-5+5)=(3,4)
please I got this: \(-5+5=0\), so we have: \(B \rightarrow (3,0)\)
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and: \(C \rightarrow (-2-4,-2+5)=...?\)
(-6, 3)
that's right!
@Michele_Laino
What is the image of A(−6,3) ?
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it is: \(A'=(-6-4,3+5)=(-10,8)\)
I'm sorry this is the rule: (x,y)→(x+2,y−5) I got (-4,-2)
that's right!
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