Write the overall, ionic and net ionic equations for the following reaction.Hydrochloric acid (HCl) and potassium hydroxide (KOH) @nincompoop
Could you help me understand how to do this??
Well, let's start out by writing the equation: \[KOH + HCl \rightarrow H_2O + KCl\] in this reaction, we have an acid reacting with a base. to produce salt and water. Can you identify which is the acid and base and why?
Okay so the acid would be HCl right? And then the base is KOH
yes, but we're not done yet
Oh okay! And thanks so much for helping me!
A common property of ionic compounds when dissolved in water is that they split up into ions.
so NaCl when dissolved in water, won't be NaCl, and HCL won't be HCL \[NaCl \rightarrow Na^+ + Cl^-\]
what would HCl become?
uhm... HCl+?
Remember it is an acid so it's going to give up a proton. it will be H+ Cl-
Ohhh! All right
So the first step is to break up our equation into ions so in our flask this is what we have instead of \[NaCl + KOH\] What we actually have is this \[H^+ + Cl^- + K^+ + OH^- \rightarrow \]
Ohh wow! Thats really broken down
now we know that this is what happens \[H^+ + Cl^- + K^+ + OH^- \rightarrow H_2O + K^+ + Cl^-\]
That makes so much more sense!
now there is something called "spectator ions" what this means is that they don't particpate in the reaction, i.e. they don't react. can you identify them?
I dont, but it would be a negative right?
you notice how H+ and OH- combine to give us water?
Yes, I do :)
what do you notice about K+ and Cl- ?
They are both apart of the equation on either side
yeah they don't participate in the reaction they are called spectator ions. we can eliminate them.
all right!
So this is what i t becomes. \[H^+ + OH^- \rightarrow H_2O\]
Oh wow you helped so much thank yu thank you thank you!
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