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with what
oh ok
idk sorry
@UsukiDoll @zepdrix
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If 3/5 is a possible root for a linear function, then (x - 3/5) must be part of the function.
ok
I might write it as y = (x - 3/5)*5 = y = 5x - 3 which clears the decimal.
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In functional notation, f(x) = 5x - 3 f(3/5) = 5* (3/5) - 3 f(3/5) = 3 -3 = 0.
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ok
3/5 is a root of the function because it is a value of x for f(x) which has a y-value of 0. The root is an x-intercept of the graph of the function and lies on the x-axis.
Because 3/5 is a root of the f(x), the expression (x - 3/5 ) is a factor of f(x).
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