Alan estimated that he would score 140 points the next time he bowled. He actually scored 152 points.

What was the percent error in Alan’s estimate? Round to the nearest tenth of a percent, if needed.

A.
6%

B.
7.9%

C.
8.6%

D.
12%

Question

Alan estimated that he would score 140 points the next time he bowled. He actually scored 152 points.
 
What was the percent error in Alan’s estimate? Round to the nearest tenth of a percent, if needed.
 
 A.
6%
 
 B.
7.9%
 
 C.
8.6%
 
 D.
12%

kittiwitti1 · Answer

I'm not exactly sure if this is the right way to do it, but I'd
• subtract 140 from 152, which gets you the points he scored OVER his predicted score (12).
• make a fractional ratio out of the value from previous step and 140 (12/140). simplify it until you get a decimal
• convert that decimal to percentage form$$152-140=12\rightarrow\frac{12}{140}\rightarrow\frac{3}{35}\approx 0.086\text{ or }8.6\text{%}$$

purple_pink · Answer

woah! thanks! :D

kittiwitti1 · Answer

I don't know if this is the correct method, though. I'd ask another person just to make sure  ♦

purple_pink · Answer

Sure

kittiwitti1 · Answer

Also, random trivia: if you look at the last four letters in your question's URL ... ☻

purple_pink · Answer

yes?

kittiwitti1 · Answer

Just look at it: http://openstudy.com/study#/updates/56e86a50e4b093c37491dead

kittiwitti1 · Answer

lol ☻

purple_pink · Answer

oh loooooool

kittiwitti1 · Answer

Well, I asked a math pro on here to check my work. Looks like I did it right.
Thanks @agent0smith ♥

Good luck on your studies, @purple_pink ♣

purple_pink · Answer

thank you sooo much do you mind helping me with 2 more?

kittiwitti1 · Answer

Sure, just post a new question ♪

purple_pink · Answer

i know thanks!

kittiwitti1 · Answer

No problem ♫