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What is the second term in the expansion of (2x + 7)6? 1344x4 23,520x5 1344x5 23,520x4
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(r + 1)th term of (a + b)^n= nCr a^(n-r)b^r
in this case r = 1, n = 6 , a = 2x and b = 7
so (2x+7)^6= 6^(6-1)???
no 6C2 (2x)^5 * 7^1
Sorry that' s nC1 which = 6
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(2x)^5 = 32 x^5 and 7^1 = 7
so 32x^5*7
6C1 = 6
you forgot the 6
6C1 * 32x^5 * 7 = 6 * 32x^5 * 7
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32x^5 * 42
right Now sismplify some more
ok so how would i simlify it more ??
just multiply 32 by 42
1344x^5 right
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yes Thats the 3rd choice
ok thank yo
yw
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