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Geometry 7 Online
OpenStudy (sbuck98):

Does anyone know much about finding/ counting area?

OpenStudy (sbuck98):

OpenStudy (mathmusician):

I can help

OpenStudy (sbuck98):

Thank you! @mathmusician

OpenStudy (mathmusician):

Does that graph have x and y values?

OpenStudy (sbuck98):

No:/

OpenStudy (sbuck98):

for the height would I count directly through the center?

OpenStudy (sbuck98):

I'm having trouble figuring it out because it's not full squares.

OpenStudy (mathmusician):

I'm not to sure on how to do this one then. @Jaynator495 can you help?

OpenStudy (sbuck98):

I think they height of it might be 1 1/2 squarefoot. But, I don't know, it's confusing..

OpenStudy (sbuck98):

But, I also need help with circles too, if you know how to do that you might be able to explain to me how to do that. @MathMusician

OpenStudy (mathmusician):

Do they have x and y values

OpenStudy (sbuck98):

This is my circle problem

OpenStudy (mathmusician):

Well the total angle has to be equal to 360 degrees

OpenStudy (mathmusician):

you have 128 and 90 so far that is a total of 218

OpenStudy (sbuck98):

So the other one would be 142? 360-218=142.

OpenStudy (sbuck98):

Never mind, that's not a option.

OpenStudy (mathmusician):

The angle that is adjacent (the one o the right) to the 90 degrees on is also 90 degrees now you have a total of 308

OpenStudy (mathmusician):

360-308 gives you the last angle which is 52 But the question asks for TCB

OpenStudy (mathmusician):

Now you want to add up all of the values that are in between TCB so... 128 + 52 + 90 = ?

OpenStudy (sbuck98):

270

OpenStudy (mathmusician):

Yep

OpenStudy (mathmusician):

Good job!

OpenStudy (sbuck98):

Can you help me with a few more?

OpenStudy (mathmusician):

I have to write an essay right now but there are other people who can help you.

OpenStudy (sbuck98):

No one ever helps me on here:(

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