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OpenStudy (anonymous):
of sin theta =2/3 find cos theta show work i need help asap
edit-hint sin 2 theta+ cos2 theta = 0
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Nnesha (nnesha):
|dw:1458155131189:dw|
you should be familiar with\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]
Nnesha (nnesha):
so draw a right triangle
given is sin theta =2/3
so what would be opposite side of theta ?>
OpenStudy (anonymous):
idk tbh im not good at this
OpenStudy (anonymous):
adjacent?
Nnesha (nnesha):
\[\huge\rm \sin \theta =\frac{\color{REd}{opposite}}{\color{blue}{hypotenuse}}=\frac{\color{red}{2}}{\color{blue}{3}}\]
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OpenStudy (anonymous):
and then
Nnesha (nnesha):
numerator = length of opposite side
denominator = length of hypohtunse side
Nnesha (nnesha):
i just saw the hint
you can use that as well
substitue sin for 2/3 and then solve for cos
OpenStudy (anonymous):
can you write out the steps
OpenStudy (anonymous):
to all i need t see it
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Nnesha (nnesha):
the hint should be this \[\huge\rm \sin^2 \theta + \cos^2 \theta =1\]
equal to 1 not 0 ?
OpenStudy (anonymous):
oh my bad
OpenStudy (anonymous):
you are right sorry lol
Nnesha (nnesha):
its okay that's the MOST famous identity
alright you can use that equation to find cos
substitute sin for 2/3
OpenStudy (anonymous):
so 2/3+cos theta=1
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Nnesha (nnesha):
\[\huge\rm \sin^2 \theta + \cos^2 \theta =1\] \[\huge\rm (\frac{2}{3})^2 + \cos^2 \theta =1\]
solve for cos
Nnesha (nnesha):
don't forget the squares
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
help me solve?
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