In the chemical reaction where N2O4 (g) is converted to 2NO2 (g), if 0.5 M N2O4 and 0.15 M NO2 are in the vessel, is the reaction at equilibrium? If, not, which direction would the reaction proceed? ( Kc = 4.4 x 1p^-3) N2O4 (g) = 2NO2 (g)
A. No, Q= 0.18 so the reaction should proceed in the forward direction B. No, Q= 9.0 x 10^-2 so the reaction should proceed in the reverse direction C. No, Q= 4.5 x 10^-2 so the reaction should proceed in the reverse direction D. Yes, the reaction is at equilibrium
Write the Kc expression for the given equilibrium using the concentrations given and see if the obtained Kc value is equal to the Kc value given in the question
Write the Kc expression for the given equilibrium using the concentrations given and see if the obtained Kc value is equal to the Kc value given in the question \[Kc = \frac{ [NO2]^{2} }{ [N2O4] }\] \[Kc = \frac{ [0.15]^{2} }{ 0.5 }\]
I got 0.045 So C is the answer ? @Rushwr
yes yes :)
@Rushwr Thankyou so much
no problem :)
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