Please Help! How can one fifth x − 2 = one third x + 8 be set up as a system of equations? (6 points) 5y − 5x = −10 3y − 3x = 24 5y − 5x = −10 3y + 3x = 24 5y + x = −10 3y + x = 24 5y − x = −10 3y − x = 24
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A problem expressed in words like this can be too much trouble for some potential helpers to decipher. "How can one fifth x − 2 = one third x + 8 be set up as a system of equations?" I'd suggest you enclose that "one fifth" inside parentheses: (1/5)x - 2 and that you also enclose that "one third" likewise: (1/3)x + 8 Set each of these expressions = to y. Type out the resulting equations. These constitute your "system of linear equations." Obviously, y = y, so set the two expressions above = to each other. This eliminates y. How would you then find x? How would you then find y?
You would eliminate to find 'y' and plug it in to find 'x' right?
yes
Actually, you'd do those two things in the reverse order: x first, y second.
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