So I worked this problem out and I just want to know if I did it correctly. I'll upload the problem and then my steps.
This is a parallelogram ABCD, and it says AB = 2y + 1, BC = y+ 1, CD = 7x-3 and DA=3x. Find the missing values
So here is what I did: 1. 2y + 1 = 7x - 3, y=7/2x-2 2. 7/2x-2+1=3x, x = 2 3. 2y + 1 = 7(2)-3, which got me y=5, so I got y=5 and x=2
looks correct :)
Yay! Thank you :)
1. why - 2 and not - 4 ?
+1 on the other side with -3 make -4 or not ?
It just makes sense to me this way, I don't really see what you are saying.
on the first point 2y+1= 7x-3 2y = 7x-4 y = (7x-4)/2
Ah I see, well, that's just another way to do it I guess. This is just where my brain jumps to.
so this is bc dont use where necessary parantheses
but i checked it step by step and really this is true right ,correct
so was my pleasure good luck bye bye
Thank you very much for letting me know :)
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