Instant fan/medal: Find the exact value of the slope of the line which is tangent to the curve given by the equation r = 1 + cos θ at pi/2=theta.
find the gradient first
Do you have the expression for gradient?
@FaiqRaees I don't even know what a gradient is unfortunately, my online course is pretty vague. This is my first time working with polar curves :)
Do you know differentiation?
I am not able to help you if you wont respond.
@FaiqRaees yes I do know differentiation, but I am not sure how complex the problem is yet
Okay so to differentiate y First differentiate 1 Whats the answer?
d/dx of 1 = 0?
Perfect Now differentiate cos θ
-sin(theta)
Very good d/dx y = 0+ (-sin θ) d/dx y = -sin θ
Do you understand how we arrived at the concluded gradient?
yes we derived the polar curve
Okay now we have to find the gradient at θ=π/2 so substitute θ=π/2 in the equation of gradient and find out the gradient at θ=π/2.
-sin(pi/2)=-1
Yes very good. Now we have the gradient of our tangent. All we need is a point which lies on the tangent. Any idea how can we figure out that point?
graph?
We can do that but its complicated. What we will do is, we know that tangent touches the curve at θ=π/2. Which means the coordinate at θ=π/2 will lie both on the curve and the tangent. Agree?
Yep :)
So substitute θ=π/2 in the equation of curve to find the y coordinate at θ=π/2
1+cos(pi/2)=1
so our coordinates are (π/2,1) Now substitute the coordinates in the equation y= -x+c (where c is a constant to be found)
Confused?
1=-pi/2 +c, c=1+(pi/2) ? @FaiqRaees sorry for slow response there
yes now substitute the value of c in y= -x+c
y=-x+1+pi/2
yes correct, there you have the equation of tangent
So how do I go about finding slope now?
Oh btw I am really really sorry, I misread the questio, the question was way shorter. After finding the derivative, you just had to plug θ=π/2 and you would have your answer -1
lol it's fine ! Thank you for everything @FaiqRaees
dy/dx = -sinθ dy/dx = -sin(π/2) dy/dx = -1 Slope =-1
Join our real-time social learning platform and learn together with your friends!