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Mathematics 6 Online
OpenStudy (jskinny0831):

can someone show me this graphed? f(x)=6sin(θ + 30°) + 3

OpenStudy (mathmale):

What is the amplitude of this graph? What is the phase shift? left or right? how great a phase shift? Graph the basic sine function as a starting point. Can you recognize the vertical shift that takes place here? Explain how you'd move the graph of the sine function up or down if the last term is 3.

OpenStudy (jskinny0831):

the amplitude is 6

OpenStudy (jskinny0831):

the phase shift is 30 units left

OpenStudy (jskinny0831):

im just having trouble graphing it

OpenStudy (faiqraees):

Thes best way is in my opinion find the period, divide it by four and call the number x. Substitute x, 2x , 3x, 4x in the equation and note down the coordinates. Plot accordingly

OpenStudy (mathmale):

Your best bet would be to tackle the graphing step by step. 1) graph y=sin x 2) graph y=6 sin x 3) shift the graph 30 degrees to the left 4) shift the graph up or down as specified by that final '3'

OpenStudy (jskinny0831):

okok thank you so much, got it!

OpenStudy (mathmale):

the coefficient of theta is 1. If that's the case, what is the period of this function? My pleasure.

OpenStudy (jskinny0831):

the period is 360 divided by b but since there is no b then its divided by 1 so its just 360 for the period

OpenStudy (mathmale):

"There is no b." Not so! If there's no coefficient in front of that variable x, then your coefficient is 1. Your period is 2pi/1 = 2pi, or 360 deg.

OpenStudy (jskinny0831):

oh ook thank you! i got my question correct

OpenStudy (jskinny0831):

thanks for the help, im good now!

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