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okay for a question i had a minute ago I have created a function which looked like this (ill write it in the comments so I can use the symbols
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\[f(x)=1(x-1)^2+4\] This is a function we had to made using our birth date and being that I am january 4th it is fairly simple. With me doing that I went then to this: \[f(x)=1(x-1)(x-1)+4\]
once I did this i distributed and got: \[f(x)=x^2-2x+5 \] would this be putting my function into standard form from it being in vertex form?
@rebeccaxhawaii
ax+bx=c this is standard form
okay so from vertex form which i have above how would i go to standard?
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@Michele_Laino mind helping if you have a second?
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