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\[\large \bf f(x)=\sin^{-1}(\frac{1+x^2}{2x})\] where, \[\large x \rightarrow 1^-\]
find the value of \[\large \bf f(1^-)\]?
@ganeshie8 @Kainui
.
What does it mean ?
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@zepdrix
isn't the answer -pi/2 ?
he means \(+\pi/2\) by simply plugging in x = 1 in f(x)
Options are :- \[\large \bf A) \sin^{-1}(1^+)\] \[\large \bf \ B) sin^{-1}(1^-)\]
@ganeshie8
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@hartnn what do you think ?
\(\Large \dfrac{1+(1^-)^2}{2\times 1^-}\) which one do you think is greater? numerator or denominator?
numerator
you may take simple example of 0.9 :)
yes correct!
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so, the fraction is >1 but very near to 1 which means --> \(1^+\)
okay !
thanks for you help :)
welcome ^_^
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