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Mathematics 12 Online
OpenStudy (anonymous):

Question on Limits

OpenStudy (anonymous):

\[\large \bf f(x)=\sin^{-1}(\frac{1+x^2}{2x})\] where, \[\large x \rightarrow 1^-\]

OpenStudy (anonymous):

find the value of \[\large \bf f(1^-)\]?

OpenStudy (anonymous):

@ganeshie8 @Kainui

ganeshie8 (ganeshie8):

.

OpenStudy (anonymous):

What does it mean ?

OpenStudy (anonymous):

@zepdrix

ganeshie8 (ganeshie8):

isn't the answer -pi/2 ?

hartnn (hartnn):

he means \(+\pi/2\) by simply plugging in x = 1 in f(x)

OpenStudy (anonymous):

Options are :- \[\large \bf A) \sin^{-1}(1^+)\] \[\large \bf \ B) sin^{-1}(1^-)\]

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@hartnn what do you think ?

hartnn (hartnn):

\(\Large \dfrac{1+(1^-)^2}{2\times 1^-}\) which one do you think is greater? numerator or denominator?

OpenStudy (anonymous):

numerator

hartnn (hartnn):

you may take simple example of 0.9 :)

hartnn (hartnn):

yes correct!

hartnn (hartnn):

so, the fraction is >1 but very near to 1 which means --> \(1^+\)

OpenStudy (anonymous):

okay !

OpenStudy (anonymous):

thanks for you help :)

hartnn (hartnn):

welcome ^_^

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