Question

First derivative of sec^2(x).
I'm getting different answers online and I'm having trouble identifying which one is correct. Could you do a step by step explanation?

Answer 1

you know that \( (\sec x )' = \sec x \tan x\) ??

so you can chain it.

Answer 2

so \( (u^2)' = 2 u u' \) and u = sec x, if you like

Answer 3

So would the answer be 2sec^2(x)tan(x)?

Answer 4

y!

Answer 5

\[2\sec^2(x)\tan(x) \]

Answer 6

Thank you!

Answer 7

mp :-)