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What number must be added to both sides of the equation to complete the square? x^2 - 16x = -8
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Nope. (x-8)(x-8) =x^2-16x+???
Whayt is that...
Can you simplify (x-8)*(x-8)?
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one sec
(x - 8)^2?
Yeah
So do I solve for x now? srry i'm new to this..
@Aveline Are you busy?
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Oh sorry I was walking to my next class. What number must be added to both sides of the equation to complete the square? x^2 - 16x = -8 The first step is to divide -16x in two, it is -8x. Using this, we can write the first part of the square: (x-8)(x-8) or (x-8)^2 If we FOIL this out, we get: x^2-8x-8x+64 =x^2-16x+64 You will have to add 64 to each side: x^2-16x+64=56
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