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Mathematics 18 Online
OpenStudy (leonardo0430):

can someone help me on this

OpenStudy (leonardo0430):

OpenStudy (leonardo0430):

answer my question first ;^)

OpenStudy (vishweshshrimali5):

Similarity basically means that ratio of corresponding sides be same...

OpenStudy (thatawayz):

the larger ones measurements are 4 times that of the smaller

OpenStudy (dinamix):

\[\frac{ 8 }{ y-2 }=\frac{ 16 }{ 4 }\] @leonardo0430

OpenStudy (leonardo0430):

one side is 4 while the other side is 16, meaning the the big shape is 4 times bigger than the small shape, but i am having trouble picking the right answer

OpenStudy (dinamix):

this is first step

OpenStudy (leonardo0430):

^ would that be 2?

OpenStudy (leonardo0430):

i know y, but not x

OpenStudy (thatawayz):

okay, we already know one4th of 8 is 2 so what minus 2 equals 2?

OpenStudy (thatawayz):

y-2=2

OpenStudy (leonardo0430):

yes i know 4, it could be either A or D, but the part i dont get is X

OpenStudy (thatawayz):

okay, just read that you know y, that already narrows it down to only 2 possible answers

OpenStudy (leonardo0430):

but isnt x-3 sid and 8 suppused to be the same sides?

OpenStudy (thatawayz):

because the rest of the lengths of the pentagon are even, i would assome x is even aswell, so 28???

OpenStudy (leonardo0430):

could you explain how you got that answer?

OpenStudy (thatawayz):

the image is kind of weird, it may look even but it isnt necesarily accurate

OpenStudy (thatawayz):

that was a raw guess,

OpenStudy (thatawayz):

perhaps its like this, the smaller pentagon has values 2, 4, 6. the large one appears to have, 8,16, 24

OpenStudy (leonardo0430):

oh i see your point, that does seem like a pattern thanks alot :)

OpenStudy (thatawayz):

so it actually might be 27, so x - 3 is 24

OpenStudy (thatawayz):

27-3, pardon

OpenStudy (thatawayz):

mathematics these days... gahhhhhh

OpenStudy (leonardo0430):

thankyou for your help i get it now t i was stuck on this one for sometime hanks once again :)

OpenStudy (thatawayz):

no problem, glad i could help!!!

OpenStudy (leonardo0430):

do you think you could help me on my final question? ill tag you in it

OpenStudy (thatawayz):

i can certainly try it!!!

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