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Mathematics 20 Online
OpenStudy (howard-wolowitz):

If four cards are drawn from a standard deck of 52 cards and NOT replaced, what is the probability of getting at least one heart? HINT: Use the idea of the complement.

OpenStudy (howard-wolowitz):

Im not sure about this one hartann

hartnn (hartnn):

atleast 1 = 1- none

hartnn (hartnn):

first find the probability that ALL the cards are NOT hearts

OpenStudy (howard-wolowitz):

i think the answer is It is 1 - ((39/52) * (39/51) * (39/50) * (39/49)) or 1 - (.75 * .7647 * .78 * .795918) or 1 - .3560535 or 0.6439

hartnn (hartnn):

almost! note that the cards are not replaced. so at first there are 39 non-heart cards, then there will be 38 ... 1 - ((39/52) * (38/51) * (37/50) * (36/49))

hartnn (hartnn):

makes sense?

OpenStudy (howard-wolowitz):

no

OpenStudy (howard-wolowitz):

why will there be 38

hartnn (hartnn):

say you chose King of Spades. you did not put it back. out of 39, this one was removed hence 38

OpenStudy (howard-wolowitz):

ok i see

OpenStudy (howard-wolowitz):

the two answers i am getting here are .6439 and .6962

hartnn (hartnn):

why 2? its just 0.6962

OpenStudy (howard-wolowitz):

well you got 2 on your 0.6962

hartnn (hartnn):

lol i mean why do you have 'two' answers :P 1 - ((39/52) * (38/51) * (37/50) * (36/49)) = 0.6962 is the correct one :3

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