If four cards are drawn from a standard deck of 52 cards and NOT replaced, what is the probability of getting at least one heart?
HINT: Use the idea of the complement.
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OpenStudy (howard-wolowitz):
Im not sure about this one hartann
hartnn (hartnn):
atleast 1 = 1- none
hartnn (hartnn):
first find the probability that ALL the cards are NOT hearts
OpenStudy (howard-wolowitz):
i think the answer is It is 1 - ((39/52) * (39/51) * (39/50) * (39/49))
or 1 - (.75 * .7647 * .78 * .795918)
or 1 - .3560535
or 0.6439
hartnn (hartnn):
almost!
note that the cards are not replaced.
so at first there are 39 non-heart cards,
then there will be 38 ...
1 - ((39/52) * (38/51) * (37/50) * (36/49))
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hartnn (hartnn):
makes sense?
OpenStudy (howard-wolowitz):
no
OpenStudy (howard-wolowitz):
why will there be 38
hartnn (hartnn):
say you chose King of Spades.
you did not put it back.
out of 39, this one was removed
hence 38
OpenStudy (howard-wolowitz):
ok i see
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OpenStudy (howard-wolowitz):
the two answers i am getting here are .6439 and .6962
hartnn (hartnn):
why 2?
its just 0.6962
OpenStudy (howard-wolowitz):
well you got 2 on your 0.6962
hartnn (hartnn):
lol i mean why do you have 'two' answers :P
1 - ((39/52) * (38/51) * (37/50) * (36/49)) = 0.6962 is the correct one :3