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OpenStudy (anonymous):
the function f is defined by f(x)=2x^2-1 find f(2y) .......can someone help me please will medal
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OpenStudy (faiqraees):
you haven't written the correct question
OpenStudy (faiqraees):
Is it "find f(2y)"
OpenStudy (anonymous):
yes i changed it :)
OpenStudy (anonymous):
@FaiqRaees
OpenStudy (faiqraees):
Okay so in place of x write 2y and rewrite the function
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OpenStudy (faiqraees):
\[\large\rm f(x)=2x^2-1 \]\[\large\rm f(x)=2(2y)^2-1 \]
OpenStudy (anonymous):
oh ok i wrote it wrong
OpenStudy (faiqraees):
No you didnt write it wrong. The equations I wrote are part of the solution
OpenStudy (anonymous):
ok so would you take 2y times 2y then times it by 2 or am I way off base
OpenStudy (anonymous):
@FaiqRaees
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OpenStudy (faiqraees):
correct
OpenStudy (faiqraees):
\[\large\rm f(x)=(2*2y*2y)-1 \]
OpenStudy (anonymous):
so would it be f(x) =8y-1 @FaiqRaees
OpenStudy (faiqraees):
No y times y is y squared
so 2y times 2y is 4 y squared
and 4 y squared times 2 is 8 y squared
OpenStudy (anonymous):
oops i forgot my squared
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OpenStudy (anonymous):
would I write it as f(2y)=8y^2-1
OpenStudy (anonymous):
@FaiqRaees
OpenStudy (faiqraees):
Perfect
OpenStudy (anonymous):
Thank you so much
OpenStudy (anonymous):
@FaiqRaees
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OpenStudy (faiqraees):
You are welcome
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