Factor completely 3ab(x + 1) − 2(x + 1) How would i do this? Explian ?
note that (x + 1) is common to the 2 parts of the expression
I see subtraction in this expression. One term is to be subtracted from the other. What are the two terms? What do these two terms have in common? Factor out the common factor.
if we take out (x + 1) what is left?
3ab-2 ?
Great. Now, please write the original expression in factored form.
It would be (x+1) (3ab-2)
thats correct
What if i have a trinomial equation? Would i do the same thing or is it a whole different process ?
lets say this is my equation 3x^2 + 2x − 1 What would i do ?
you could use a similar process as a part of factoring a binomial
ok take the first and last coefficients which are 3 and -1 , Note that 2x = 3x - x so we can write 3x^2 + 3x - x - 1 now we can factor that by pairing in a similar way to the one in your original question Any ideas?
Hint: What do the first 2 terms have in common?
Hint - place last 2 terms in parentheses
(3x-1) (x-1) ?
what's a sure-fire way to check your results?
not negative!
Distributiv property ?
Meaning what?
Ive got to check my equation by using distributive property
What action must you take to check your factors? distrubutive property: yes. It's actually "Distributive Property of Multiplication."
3x-1) (x+1)
first multiply the x + 1 by 3x then do the same with -1 what do you get?
I got 4x(x+1)
youve gone wrong somewhere
the big question here is whether or not "what you got" is the same as the original expression which you were told to factor. Is it?
Please show each step of your multiplication: (3x-1) (x+1)
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