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Mathematics 5 Online
OpenStudy (anonymous):

The graph shows a cubic function. https://hanwingspanps.owschools.com/media/g_alg02_ccss_2015/7/img_alg2u07l13_08.gif

OpenStudy (anonymous):

@Ciarán95

OpenStudy (welshfella):

what is the question?

OpenStudy (anonymous):

how many real roots does the function have.....i think its three

OpenStudy (welshfella):

yes Do you know what they are?

OpenStudy (anonymous):

intersections at the line maybe

OpenStudy (welshfella):

yes at the intersection of the line with the x-axis (when f)x) = 0)

OpenStudy (anonymous):

so how would i complete the graphed function than

OpenStudy (welshfella):

we have an intersection at x = 1 so thats one root The other 2 are 'double' roots - where the graph just touches x = -2 so the 3 roots are 1, -2 (multiplicity 2)

OpenStudy (anonymous):

y=(x- ) (x+ )^2 so what would i put in the blanks of this equation intresections of the x axis?

OpenStudy (anonymous):

2 an then 1 ?

OpenStudy (welshfella):

(x - __) = 0 and (x +__) = 0 just replace the __ by 1 and -2

OpenStudy (welshfella):

* (x + __)^2 = 0 i should have written

OpenStudy (anonymous):

it wont let me put -2 as an awnser .......thats why i put it in the first equation

OpenStudy (anonymous):

first part of the equation*

OpenStudy (welshfella):

oh sorry my mistake its 2 goes there not -2

OpenStudy (welshfella):

because if (x + 2)&2 = 0 then x = -2

OpenStudy (anonymous):

okay thankyou

OpenStudy (welshfella):

yw

OpenStudy (anonymous):

oh i see

OpenStudy (welshfella):

and (x - 1) = 0 gives x = 1

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