What is the value of y so that AB with endpoints A(1, y) and B(6, −1) is parallel to CD with points C(1,2) and D(-4,-2)??
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OpenStudy (jskinny0831):
can someone help me? i just need the equation on how to do it. I've been stuck on this for an hour
OpenStudy (faiqraees):
Okay whenever the direction between two pair of points is parallel. The gradient of both of them is same
OpenStudy (anonymous):
Parallel lines have the same slope. The slope equation is
\[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]
Plug int he values for each of your segments and set the slopes equal to solve for your "y"
OpenStudy (faiqraees):
So
\[\large\rm \frac{y_2-y_1}{x_2-x_1} =\frac{y_3-y_4}{x_3-x_4} \]
OpenStudy (jskinny0831):
okay so -1-y/6-1 = -2-2/-4-1 ?
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OpenStudy (anonymous):
yes
OpenStudy (faiqraees):
yep
OpenStudy (jskinny0831):
so how do i get y? im still kinda confused
OpenStudy (faiqraees):
Solve it
OpenStudy (faiqraees):
-1-y/5 = -4/-5
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OpenStudy (jskinny0831):
-1-y/5=-4/-5
OpenStudy (jskinny0831):
yeah i got that
OpenStudy (anonymous):
then cross multiply
OpenStudy (anonymous):
-5(-1 - y) = -4(5)
OpenStudy (jskinny0831):
-5-5y=-20
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OpenStudy (jskinny0831):
-5y=-20+5
OpenStudy (jskinny0831):
-5y=-15
OpenStudy (anonymous):
whoa hold up
OpenStudy (jskinny0831):
oh wait am i doing it wrong..?
OpenStudy (anonymous):
you just made a mistake distributing. it should be
5 - 5y = -20
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OpenStudy (jskinny0831):
ohh i see where i made the mistake
OpenStudy (jskinny0831):
so -5y=-20-5
OpenStudy (jskinny0831):
-5y=-25
OpenStudy (jskinny0831):
-25/-5
OpenStudy (jskinny0831):
y=5?
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OpenStudy (anonymous):
yep
OpenStudy (jskinny0831):
thank you so much!
OpenStudy (faiqraees):
(-1-y/5) x 5=(-4/-5)x5
-1-y = -4/-1
-1-y = 4
-y = 5
y = -5
OpenStudy (jskinny0831):
wait so i did it wrong?
OpenStudy (faiqraees):
You did a mistake
-5(-1 - y) = -4(5)
5+5y = -20
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OpenStudy (anonymous):
oh @FaiqRaees is right. I messed up the distribution as well