Which graph best represents the function f(x) = 1(1.5)x?
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OpenStudy (fairy733189):
i'll attach the image
OpenStudy (fairy733189):
OpenStudy (fairy733189):
OpenStudy (bobo-i-bo):
Consider x=0
OpenStudy (fairy733189):
Hang on there's still more
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OpenStudy (fairy733189):
OpenStudy (vishweshshrimali5):
@Fairy733189 also check whether the function is really 1(1.5)x
OpenStudy (fairy733189):
OpenStudy (fairy733189):
Sorry the x is an exponent
OpenStudy (vishweshshrimali5):
Great! So, \(f = 1*1.5^{x}\) ?
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OpenStudy (fairy733189):
Yes!!!
OpenStudy (vishweshshrimali5):
Great! Okay so as Bobo-i-bo said, what will be value of f when x = 0 ?
OpenStudy (fairy733189):
Would it be 1 since 1.5 to the 0 power = 1 and 1 * 1 = 1
OpenStudy (vishweshshrimali5):
Perfect!
OpenStudy (vishweshshrimali5):
Now, see which of the option has y = 1 at x = 1
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OpenStudy (vishweshshrimali5):
Sorry at x = 0
OpenStudy (fairy733189):
Let me check
OpenStudy (vishweshshrimali5):
Sure
OpenStudy (fairy733189):
Option 2
OpenStudy (fairy733189):
?
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OpenStudy (vishweshshrimali5):
Perfect!!
OpenStudy (fairy733189):
Awesome. But am I always supposed to substitute x with 0 or can it be with any number?
OpenStudy (vishweshshrimali5):
It can be any number and you can find out the value of function at that x,... then your graph should have y = value of function you got and x = value you assumed for x...
OpenStudy (fairy733189):
Ok but I don't e=really understand it because I substituted 2 but it wasn't correct on the graph
OpenStudy (fairy733189):
Can you please explain it to me?
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OpenStudy (vishweshshrimali5):
Yeah sure... we are talking of the same question? \(f = 1 * 1.5^x\)
OpenStudy (fairy733189):
yes!
OpenStudy (vishweshshrimali5):
Great! Now, when I put x = 2 => f = 1 * 1.5^2 = 1 * 2.25 = 2.25
OpenStudy (fairy733189):
Yes thats what I got but wouldn't it be like that on the graph. I just don't understand that part because when the y = 2 x would = 2.25 but the graph isn't like that
OpenStudy (vishweshshrimali5):
See at x = 2, the graph is just a bit above 2... that shows that graph is close enough.. is that actually 2.25 we can't say.. but then we are just looking for best alternative
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OpenStudy (fairy733189):
Oh ok I see it now
OpenStudy (fairy733189):
Thank you so much!!!
OpenStudy (fairy733189):
I have another problem I need help with. I am going to close this one and open a new one. Can you help me with it too?