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Mathematics 15 Online
ganeshie8 (ganeshie8):

Given a circle, what are various interesting ways to find its center ?

ganeshie8 (ganeshie8):

Here is one way I am familiar with : http://www.mathopenref.com/constcirclecenter.html it uses the fact that the perpendicular bisector of any chord of the circle passes through the center of the circle

rishavraj (rishavraj):

I wasnt familiar with even tht one -_-

Miracrown (miracrown):

So in regards to be given a circle, are you provided with any other info about the circle?

Miracrown (miracrown):

Looking at the link, it is basically a construction for locating for the center point

OpenStudy (yttrium):

I think not @Miracrown

ganeshie8 (ganeshie8):

are you from india ? if so, these constructions are taught in 8th grade math... these are not hard but easy to forget yeah :)

rishavraj (rishavraj):

@ganeshie8 its bcoz if we draw perpendicular from the centre to the chord...it bisects them ??

rishavraj (rishavraj):

Myyy bad I got confused...and now when I think I m so dumb to forget tht .....

ganeshie8 (ganeshie8):

here is the actual problem @Miracrown http://www.euclidea.xyz/en/game/#/packs/Alpha/level/CircleCenter

ganeshie8 (ganeshie8):

i don't seem to work it in less than 6 steps...

ganeshie8 (ganeshie8):

im sure you're not dumb @rishavraj it just takes some review to refresh these again in your head :)

rishavraj (rishavraj):

lol thts the reason I jst started to give tution classes..... :P

ganeshie8 (ganeshie8):

thats the reason i login here frequently too :)

OpenStudy (yttrium):

I think I know another method. Try to draw four tangent lines in the circle to form a square and draw its diagonals..

ganeshie8 (ganeshie8):

that is interesting @Yttrium but the tangent construction itself requires the center to be constructed first right ?

OpenStudy (freckles):

how about folding

OpenStudy (freckles):

you only need two folds

ganeshie8 (ganeshie8):

ahh folding works like a charm! you want to fold twice to get two perpendicular bisectors right ? i think its still equivalent to 6 steps for euclid...

OpenStudy (freckles):

yeah two perpendicular bisectors

ganeshie8 (ganeshie8):

then your method is equivalent to mine, just the tools are different i guess

Miracrown (miracrown):

I'm thinking of one that is not equivalent to yours hmm...

ganeshie8 (ganeshie8):

@Yttrium by triangular ruler you mean the set squares ? http://www.draftex.com.au/image-optimise.ashx?imageId=1274&imageSize=4

OpenStudy (freckles):

can we use coordinate geometry ?

ganeshie8 (ganeshie8):

im wondering if we can somehow use below fact to our advantage https://i.ytimg.com/vi/eo0_I2jjy6k/maxresdefault.jpg

OpenStudy (freckles):

the coordinate geometry way i think sorta steels @yttrium 's idea of creating a square though well the one I'm thinking of

Miracrown (miracrown):

I have one that's somewhat similar, but it doesn't require you to construct the chords. We'll start with a circle. Now, at any point on the circle, I'll use the compass to draw two arcs that are equidistant from that point, for example, from point A: |dw:1459222897163:dw|

Miracrown (miracrown):

those two arcs are (supposedly) equdistant from A... let's call those intersections B and C:

Miracrown (miracrown):

|dw:1459222986047:dw|

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