Question

Two cards are drawn from a well-shuffled standard deck of cards. Match each scenario to its probability. (in the attached file below).

Answer 1

First screenshot shows the pairs and the second shows the answers. Will medal or whatever :-)

Answer 2

1/169= 3rd scenario
1/442= 1st scenario
4/169= 4th scenario
1/52= 2nd scenario


no promises tho

Answer 3

how many cards in total ?

Answer 4

As many cards that are in normal stack I guess....so 52? Not sure.

Answer 5

the reason i put the first scenario with 1/442 is because it have specific suite and specific number so there are less to have a chance to pull.

second scenario i put with 1/52 because you have 8 cards you can pick then a chance to pick 8 cards as well.

third scenario with 1/169 because you have not as great of a chance as the second scenario. you have a chance to pull 1 of 4 cards then 1 of 4 again.

fourth scenario with 4/169 because you have a 1 of 13 cards to pick then you have a chance to pick 1 of 4 cards.

this is why i may not be correct i did not use math statistics to solve it just logic kind of.

also there are 52 cards in a deck

Answer 6

@reemii to the rescue with the answer...lol

Answer 7

I've been using common sense the entire year and it's done me okay. But my end date is Friday so these post tests are a big deal.

Answer 8

"Mutliply probabilities"
Tile 1: (red ace, then some ace) no replacement.
-> red ace: there are 2 among the 52 cards -> p1 = 2/52
-> some ace, no replacement (means some red ace is missing!!): there are 3 aces left, among 51. -> p2 = 3/51.
Answer for Tile1 : (2/52)(3/51) = (1/26)(1/17) = 1/442.

Answer 9

Same reasoning for others.
It is important to keep in mind that without replacement, the deck is modified before the second draw. With replacement, the deck is complete (52 cards).

Answer 10

Thank you both very much! :-))

Answer 11

Tile 2. (3 or 5, then 4 or 6) with replacement.
-> 3 or 5: 2 cards among 52 -> p1 = 2/52
-> 4 or 6 (complete deck!!): 2 cards amogn 52-> p2 = 2/52
=> answer: (2/52)(2/52) = 1/676... not in the options! omg ...

Answer 12

(8/52)(8/52)=(1/13)(1/13)=1/169

???

Answer 13

haha! sorry, there are four 3's, 4's, 5's, and 6's....

Answer 14

@dinah_rose is right

Answer 15

Tile3.
(king, then queen) replacement
4 kings in the deck -> 4/52
replacement, 4 queens inthe deck -> 4/52
=> (4/52)(4/52) =1/169

Answer 16

nvm the second is 4/169

Answer 17

2/13 not 1/13

Answer 18

It's fine. I solved it. Thank you!!!!!! :-)))))

Answer 19

verify you understand by solving Tile4 ;-) if you want to

Answer 20

and if you do dont just say it is 1/52 because thats to obvious...if you do show the steps

Answer 21

I've already moved on in the course. I have a huge lack of time. Thank you guys.

Answer 22

i know the feeling im three months behind in my studies

Answer 23

I feel you girl. 3 extensions later and I'm still behind. I decided to cyber for my senior year and never previously have. Didn't realize the work load. :-/ oh well

Answer 24

@dinah_rose

Answer 25

yeah it is my 10th year and i cant deal with people due to anxiety so yeah now im cyber school and yeah i took a break for funerals and stuff got 3 months behind so i defiently know how that goes