Consider two events such that P(A) = 1/6, P(B) = 3/5 , and P(A ∩ B) = 2/15. Are events A and B independent events? A. Yes, they are independent because P(A) ⋅ P(B) = P(A ∩ B) B. No, they are dependent because P(A) ⋅ P(B) = P(A ∩ B) C. Yes, they are independent because P(A) ⋅ P(B) ≠ P(A ∩ B) D. No, they are dependent because P(A) ⋅ P(B) ≠ P(A ∩ B)
i really need help again @mathmale can you help me please?
Memory rusty. So, I did an Internet search on your behalf. Please see: https://www.wyzant.com/resources/lessons/math/statistics_and_probability/probability/further_concepts_in_probability
As much as I'd like to help further with this, I'm declining. Been a long day for me.
In this case, we judge whether two events are dependent or not by whether "the probability of B happening, given that A has happened) is the SAME as "the probability that B has happened." In other words, A having happened doesn't affect P(B).
The definition of two events being independent: A and B are independent if\[P(A)P(B)=P(A\cap B)\]and if [P(A)P(B)=P(A\cap B)\] then A and B are independent
they are independent events because P(A) and P(B) did not equal P(A n B)
so it must be C
Nono, reread the defintion
If P(A)P(B)=P(AnB), then A and B are independent
so the answer has to be independent right not dependent, either A or C right?
since they do not rely on each other so it can't be dependent @Bobo-i-bo
it didn't say they were independent in the question, it was asking if they are so it is C i think
No :P
then what
i already submitted the answer and got it wrong
As I said, if \[P(A)P(B)=P(A \cap B)\] then A and B are independent. Therefore if: \[P(A)P(B)\neqP(A \cap B) \] then A and B are not dependent
okay thanks
P(A)P(B)=1/10 which does not equal to P(AnB) so they are not independent, hence they are dependent. Therefore the answer is D.
Lol, sorry I didn't make it in time
awww man and its okay but thank you for helping me, now i get it and can do it myself if i get a question like that again!
^_^
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