Find the exact value of cos(-7pi/4)
pi meaning 3.14...?
yeah
so that would be -7 times 3.14/4
okay... so first times -7 by 3.14
which is -21.98
next divid -21.98 by 4
which gives you -5.495
\(\cfrac{7}{4}\implies \cfrac{4+3}{4}\implies \cfrac{\cancel{4}}{\cancel{4}}+\cfrac{3}{4}\implies 1+\cfrac{3}{4} \\ \quad \\ \cfrac{7\pi }{4}\implies \cfrac{4\pi +3\pi }{4}\implies \cfrac{\cancel{4}\pi }{\cancel{4}}+\cfrac{3\pi }{4}\implies \pi +\cfrac{3\pi }{4} \\ \quad \\ -\cfrac{7\pi }{4}\implies -\cfrac{4\pi +3\pi }{4}\implies -\cfrac{\cancel{4}\pi }{\cancel{4}}-\cfrac{3\pi }{4}\implies -\pi -\cfrac{3\pi }{4}\)
hope that helps :)
bear in mind that, when using a fraction of \(\pi\), is still just a fraction, so, you can siimply take the "wholes" from it, like on any fraction
@Wow2007 was that correct?
No, because they have to be in like fraction form
No, because they have to be in like fraction form
so... what quadrant did you end up at anyway?
Answer A is (sqrt)2/2 Answer B is 1/2 Answer C is (sqrt)3/2 Answer D is -1/2
I don't know, I have literally no math skills at all, I've always been way behind in math
well... have you covered negative angles yet?
Not really, these lessons are kind of everywhere. like the test before this was about surveys :/
The book helps absolutely nothing, the only thing that is in it are definitions and examples
so... if you haven't covered negative angles... how are you expected to answer it? I mean, I could ask you for my car keys only if I already know you know how to find them otherwise, it would just make no sense I mean, I could ask you just now do you know where my car keys are?
*sigh* I know, and like you have free tutoring but its literally near impossible to get ahold of a tutor and then they want you to spend like a month learning about all kinds of things and only like 5% of it is relevant.
I only have like 5 classes left (this is my last math) and i keep getting stuck on my math classes and it takes forever
well, unless you cover the material first, it won't make much sense
http://www.mathopenref.com/trigany.html <--- drag the corner over, notice when it turns negative
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