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Find the mass and center of mass of the lamina
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the lamina is bounded by x^2 + y^2 = r^2, x is greater than or equal to zero, y is greater than or equal to 0
if p(x,y) = k(x^2 + y^2)
ok so for the double integral i know that the initial equation would be k(x^2 + y^2) but could i convert that to polar which is k(r^2) dr d(theta) and get the correct answer?
sorry i meant k(r^2) r dr d(theta)
so k r^3 dr d(theta)
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\[\int\limits_{0}^{\pi/2}\int\limits_{0}^{r}kr^3 drd\]
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