Mathematics
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alones (alones):
Evaluate /:
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alones (alones):
−3√-8
alones (alones):
I got −1√-2 for my answer
OpenStudy (bobo-i-bo):
Do you know what \[\sqrt{-1} \] is?
alones (alones):
Umm. no
alones (alones):
it's squred root
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OpenStudy (bobo-i-bo):
\[\sqrt{-1}=i\]
where i is THE imaginary number... have you covered complex numbers at all?
rebeccaxhawaii (rebeccaxhawaii):
mm
alones (alones):
ofc i did.
OpenStudy (bobo-i-bo):
Okay... then notice that
\[-3\sqrt{-8}=-3\sqrt{8}\sqrt{-1}\]
Directrix (directrix):
@Bobo-i-bo Is that ^^^ the final answer?
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OpenStudy (bobo-i-bo):
No, i wouldn't give you the final answer :P
OpenStudy (bobo-i-bo):
But i'm trying to help you, lol
alones (alones):
I said my final answer already Hm._.
alones (alones):
btw i'd like a person to explain me not this sites /;
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alones (alones):
@Bobo-i-bo so that was your final answer -6i√2
OpenStudy (bobo-i-bo):
yes
alones (alones):
welp that doesn't not really looks liek the right asnwer :#
Directrix (directrix):
What about the explanation now that the assumed correct answer is known.
@Bobo-i-bo
alones (alones):
#rekt
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OpenStudy (bobo-i-bo):
\[-3\sqrt{-8}=-3\sqrt{8}\sqrt{-1}=-3\sqrt{4}\sqrt{2}i=-3*2\sqrt{2}i=-6\sqrt{2}i\]
OpenStudy (bobo-i-bo):
Understand it all?
OpenStudy (bobo-i-bo):
It follows from the property that, given numbers a and b, \[\sqrt{ab}=\sqrt{a}\sqrt{b}\]
alones (alones):
well i got the difrent answer /:
OpenStudy (bobo-i-bo):
and how did you get your answer? please may i see working?
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alones (alones):
I cannot solve this since it's undetifined