The Amazon website plans to purchase ads in a local newspaper advertising their site. Their operating budget will allow them to spend at most $2200 on this advertising adventure. They plan to run at most 20 ads. An ad will cost $50 to appear in the weekday paper and $200 to appear in a weekend edition. Prepare a graph that will represent all of the possible combinations of ads under these conditions.
I don't think you want to graph equations. I think a bar graph would best convey the information because these are only integral values. Put the number of $20 ads up the y-axis and the number of $200 ads along the x-axis. At each integer on the x-axis, draw a vertical bar up to the maximum number of $20 you could have for that number of $200 ads. For 0, you go to 20. You could have any number of $20 ads from 0 to 20 (the criteria is at most 20 ads). For 1, you go to 19. In this case you are spending at most 19*50+1*200. Continue along, but be careful. This goes 3,17; 4,16; 5,15; 6,14; 7,13; 8,12. This is 8*200+12*50 = 2200. Now when we get to 9 $200 ads, there is only enough money for 8 $20 ads. Finish this off for 10 and 11.
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