Maria will spin the arrow on the spinner 3 times. What is the probability that the arrow will stop on A, then B, then C? A. 3/256 B. 1/64 C. 1/12 D.3/4
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I think C?
@K12awesomeness @reemii
it's b) 1/64
Can you explain please (The Unit test is gonna eat me alive if idk)
sure:)
B right, Because it's 3 times the same experiment. And in each experiment, P(A)=1/4, P(B)=1.4n P(C)=1/4 and P(D)=1/4. Therefore, "A then B then C" has a (1/4) * (1/4) * (1/4) probability of happening.
Well if those are the only 3 options of a segment, then there is a 1/3 chance of landing on A, then a 1/3 chance of landing on B, then a 1/3 chance of landing on C. Multiply the fractions together to get 1/27. However that isn't one of your answers. I'm thinking that the spinner has 4 sections, meaning 1/4 chance of A, then 1/4 chance of B, then 1/4 chance of C. Multiply these together to get 1/64, which is one of your answers. That's my input anyway
thats how I figured it out..
Thanks guys! :D
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