The equation 2x2 - 2x - 12 = 0 is factored. Each factor is set equal to zero. What are these two equations?

A. 2x - 3 = 0, x + 4 = 0
B. 2x - 4 = 0, x + 3 = 0
C. 2x + 6 = 0, x - 2 = 0
D. 2x - 6 = 0, x + 2 = 0

Question

The equation 2x2 - 2x - 12 = 0 is factored. Each factor is set equal to zero. What are these two equations?

 		A.	2x - 3 = 0, x + 4 = 0
 		B.	2x - 4 = 0, x + 3 = 0
 		C.	2x + 6 = 0, x - 2 = 0
 		D.	2x - 6 = 0, x + 2 = 0

anonymous · Answer

hello

anonymous · Answer

Ok so first we factor it yes? I got 
$$(x-3)(2x+4)$$

With this we can set BOTH factors of this equation to 0, cause remember ANYTHING times 0 is always 0 so if one of these factors is zero the WHOLE THING is 0.
$$x-3 = 0$$
$$x=3$$
----
$$2x+4 = 0$$
$$x=4/2$$
$$x=2$$

anonymous · Answer

That's my only problem is that's not an option for what you gave... so hmm

anonymous · Answer

Double check B see if you accidentally flipped the signs when typing it out?

anonymous · Answer

nope not accident

anonymous · Answer

Well this is funny you can factor it both ways so... D is correct because
$$2x^2 - 2x - 12 = (2x-6)(x+2)$$
So there are zeroes at 3 and 2 just like above. That's funny never seen that before.