Anyone good at algebra two? I am doing conditional probability and cannot figure out how to get the correct answer on a certain question. It says "a box contains three blue marbles, five red marbles, and four white marbles. If one marble is drawn at random, find P(not red l not white). The correct answer is 3/8 but I'm so lost.
Given events A and B, \[P(A|B)=\frac{ P(A and B) }{ P(B) }\]
In this case, event A is the event of getting not red, event B in the event of getting not white
Helpful?
I would use 7/12 over 8/12 ? is that correct ?
@bobo-i-bo
So you're saying P(A and B)=7/12 and P(B)=8/12?
yea, I guess so.
I understand most of this unit, just this one question I don't understand
hmmm, so you are wrong for P(A and B). P(A and B)=P(not red and not white) which is the probability of getting any colour but red or white.
oh oh oh, ok, I think maybe I understand. Let me try it and see
Omg, i got it, thank you so much! haha
:)
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