a Goldsmith designed a trapezoidal pendant with the perpendicular distance between AB and CD is 6 centimeters and the area of the pendant ABCD is 36 square centimeters find the length of CD.
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OpenStudy (anonymous):
Please help me!!! Let me see the work that you did step by step.
OpenStudy (anonymous):
What is the area of a trapezoid
OpenStudy (anonymous):
A=a+b/2×h
OpenStudy (anonymous):
So how do u think u can find the height
OpenStudy (anonymous):
I don't know that's why I'm asking for help. I really have no ide!!
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OpenStudy (anonymous):
Hold on do uu have a photo of this question
OpenStudy (anonymous):
No, but I think I figured it out. Is the answer 4?
OpenStudy (anonymous):
How did u get four
OpenStudy (anonymous):
Thank you for your help!!!😆
OpenStudy (anonymous):
I put "x" for base one and just worked it out
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OpenStudy (anonymous):
Here:
A=1/2×h (base one + base two)
A= 1/2×6 (x+8)
A=3(x+8)
A= 3×8 + 3× x
A= 3x + 24 = 36
- 24. - 24
A= 3x = 12
Divide 3 on both sides and it ends up leaving you with
X= 4
after that I just checked my work by plugging it into the formula.