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How do I continue this?
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How do you continue what?
?
This
What grade level is this?
Algebra ll 11th
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subtract 8 first
then if you want a decimal use the change of base formula
how would that apply in this situation log(6)=log(731)?
if you are looking for a decimal answer you go from \[6^{3x}=781\]to \[3x=\frac{\ln(781)}{\ln(6)}\]
\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]
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how do you know it's a ln?
you can use any base
i just picked on that is on your calculator
oh okay
you could also just say \[3x=\log_6(781)\]
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I get a different answer that way
@satellite73
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