Look at the quadratic equation below. -x2 + 3 = (2x - 1)2 What is this quadratic equation written in standard form? A. 5x2 - 4x - 2 = 0 B. 3x2 - 4x - 2 = 0 C. 3x2 - 4x + 4 = 0 D. 5x2 - 4x + 4 = 0
@pooja195 @jigglypuff314 @Michele_Laino @imqwerty @KendrickLamar2014 @rebeccaxhawaii
\(-x^2 + 3 = (2x - 1)^2 \) step 1- simplify the right hand side part to do that use this identity- \((a-b)^2=a^2+b^2-2ab\) step2- bring all the terms one one side step 3- combine like terms and simplify
can u do it with me
how do i simplfiy the right side
yeah :0
* :)
how do i do \((a-b)^2=a^2+b^2-2ab\)
okay we go like this- we use this identity- \((a-b)^2=a^2+b^2-2ab\) now we look at our equation- \(-x^2 + 3 =\color{red}{ (2x - 1)^2}\) simplifying- \(-x^2+3=(2x)^2 +(1)^2 -2(2x)(1)\)
confused ): that stuff looks really complicated
its okay :) did you get that part where we used the identity?
no i did not ):
what is with the colors?
maybe if u drew it i would understand? because u dont get that );
i just used the colors to co relate that bracket thing with the identity
is there another way of doing this? or another way to show me
okay what we did was- \(-x^2 + 3 =\color{red}{ (\color{blue}{2x} - \color{green}1)^2}\) we need to expand that bracket on the right so we use this identity-> \((a-b)^2=a^2+b^2-2ab\) look at the colored thing \(\color{red}{(\color{blue}{2x} - \color{green}1)^2}\) now use this identity-> \(\color{red}{(\color{blue}a-\color{green}b)^2}=a^2+b^2-2ab\) \(\color{red}{(\color{blue}{2x} - \color{green}1)^2}=(2x)^2+(1)^2-2(2x)(1)\) so our equation becomes- \(-x^2 + 3 =\color{red}{ (\color{blue}{2x} - \color{green}1)^2}\) \(-x^2 + 3 =(2x)^2+(1)^2-2(2x)(1)\)
prntscr is blocked on school internet
i looked it up on my phone can u explain the picture
|dw:1459454886193:dw|
3-x²=(2x-1)²
are you stuck on the 2nd step?
yes
are you familiar with this identity-> \((a-b)^2=a^2+b^2-2ab\)
no, i am fimilar with ax²+bx+c=0
well in this question we need to use that identity so i suggest that you watch this video-> https://youtu.be/Gr1E7TtXQ9U it will help you clear that 2nd step
youtube is blocked on school internet
well then check out the 2nd identity given here- http://www.ask-math.com/factorization-using-identities.html
1) a2 + 2ab + b2 = (a + b)2 2) a2 – 2ab + b2 = (a – b)2 3) a2 – b2 = (a + b) (a – b) 4) x2 + (a + b) x + ab = (x + a) (x + b)
Join our real-time social learning platform and learn together with your friends!