Mathematics
10 Online
OpenStudy (marcelie):
Help in 17 . plz help
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OpenStudy (marcelie):
myininaya (myininaya):
position function is already given so assume you had no trouble evaluating the position function at t=pi/2
myininaya (myininaya):
but velocity=(position)'
speed=|velocity|
myininaya (myininaya):
acceleration=(velocity)'
OpenStudy (marcelie):
position = 4 ft
velocity =-5
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OpenStudy (marcelie):
speed = 5 ?
myininaya (myininaya):
yes
velocity =-5 ft/sec
speed = 5 ft/sec
myininaya (myininaya):
and your position=4 ft is correct
OpenStudy (marcelie):
okay so then for acceleration is the the derrtaive of velocity equation ?
myininaya (myininaya):
yes
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OpenStudy (marcelie):
acceration = -4
OpenStudy (marcelie):
can the answers be negative ?
myininaya (myininaya):
yea
OpenStudy (marcelie):
oh okay .
OpenStudy (marcelie):
can you help me with 16. please
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myininaya (myininaya):
yep let me take a look at 16
OpenStudy (marcelie):
oh okay
myininaya (myininaya):
so you know you have to find s' and s'?
myininaya (myininaya):
s''*
OpenStudy (marcelie):
sort of i have problems with that
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myininaya (myininaya):
so you know you have to find s' and s''?
OpenStudy (marcelie):
this is what i did one sec
myininaya (myininaya):
Do you know product rule ?
OpenStudy (marcelie):
yes
myininaya (myininaya):
so you know the derivative of t is 1
and the derivative of sqrt(1-t^2) is?
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OpenStudy (marcelie):
yes that would be
OpenStudy (marcelie):
|dw:1459490733383:dw|