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Mathematics 10 Online
OpenStudy (marcelie):

Help in 17 . plz help

OpenStudy (marcelie):

myininaya (myininaya):

position function is already given so assume you had no trouble evaluating the position function at t=pi/2

myininaya (myininaya):

but velocity=(position)' speed=|velocity|

myininaya (myininaya):

acceleration=(velocity)'

OpenStudy (marcelie):

position = 4 ft velocity =-5

OpenStudy (marcelie):

speed = 5 ?

myininaya (myininaya):

yes velocity =-5 ft/sec speed = 5 ft/sec

myininaya (myininaya):

and your position=4 ft is correct

OpenStudy (marcelie):

okay so then for acceleration is the the derrtaive of velocity equation ?

myininaya (myininaya):

yes

OpenStudy (marcelie):

acceration = -4

OpenStudy (marcelie):

can the answers be negative ?

myininaya (myininaya):

yea

OpenStudy (marcelie):

oh okay .

OpenStudy (marcelie):

can you help me with 16. please

myininaya (myininaya):

yep let me take a look at 16

OpenStudy (marcelie):

oh okay

myininaya (myininaya):

so you know you have to find s' and s'?

myininaya (myininaya):

s''*

OpenStudy (marcelie):

sort of i have problems with that

myininaya (myininaya):

so you know you have to find s' and s''?

OpenStudy (marcelie):

this is what i did one sec

myininaya (myininaya):

Do you know product rule ?

OpenStudy (marcelie):

yes

myininaya (myininaya):

so you know the derivative of t is 1 and the derivative of sqrt(1-t^2) is?

OpenStudy (marcelie):

yes that would be

OpenStudy (marcelie):

|dw:1459490733383:dw|

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